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Physics

Lenses

PDF
Matthew Williams
|May 20, 2026|6 min read
Converging LensCSEC PhysicsDiverging LensLensesMagnificationPaper 01Paper 02Ray DiagramsSection C

Converging and diverging lenses, principal focus and focal length, the three standard rays for ray diagrams, real versus virtual images, magnification, the lens formula, and everyday applications.

Types of Lenses

A converging (convex) lens is thicker in the middle than at the edges. It brings parallel rays of light to a real focus (the principal focus FFF) on the other side of the lens.

A diverging (concave) lens is thinner in the middle than at the edges. It spreads parallel rays apart so that they appear to come from a virtual focus on the same side as the incoming light.

Diagram of a converging (convex) lens showing parallel rays entering from the left, refracting through the lens, and converging to the principal focus F on the right; the optical centre and principal axis are labelled, and the focal length f is marked as the distance from the optical centre to F
Diagram of a converging (convex) lens showing parallel rays entering from the left, refracting through the lens, and converging to the principal focus F on the right; the optical centre and principal axis are labelled, and the focal length f is marked as the distance from the optical centre to F

The focal length fff is the distance from the optical centre of the lens to the principal focus.

Ray Diagrams

Three standard rays are used to locate an image:

  1. A ray parallel to the principal axis, refracts through the principal focus FFF (converging) or appears to come from FFF (diverging).
  2. A ray through the optical centre, passes straight through without bending.
  3. A ray through the near focal point FFF (converging) or directed toward the far FFF (diverging), emerges parallel to the principal axis.

The image is where any two of these rays intersect (or appear to intersect, for virtual images).

Image Types

Object positionImage typeImage locationCharacteristics
Beyond 2F2F2FRealBetween FFF and 2F2F2F (other side)Inverted, diminished
At 2F2F2FRealAt 2F2F2F (other side)Inverted, same size
Between FFF and 2F2F2FRealBeyond 2F2F2F (other side)Inverted, magnified
At FFFNo imageAt infinity(rays emerge parallel)
Inside FFFVirtualSame side as objectUpright, magnified

A real image is formed where refracted rays actually converge, it can be projected onto a screen. A virtual image cannot be projected, the eye traces rays backward to an apparent intersection.

Magnification

m=image heightobject height=vum = \frac{\text{image height}}{\text{object height}} = \frac{v}{u}m=object heightimage height​=uv​

where vvv is the image distance and uuu is the object distance (both measured from the optical centre). For a real image, m>1m > 1m>1 means magnified; m<1m < 1m<1 means diminished. A virtual image from a converging lens has m>1m > 1m>1 (magnifying glass).

The Lens Formula

1f=1u+1v\frac{1}{f} = \frac{1}{u} + \frac{1}{v}f1​=u1​+v1​

Sign convention: distances measured from the optical centre are positive on the side to which light is refracted (the other side from the object for a real image). A virtual image gives a negative vvv.

Example/Converging lens image distance and magnification (2022 Paper 02, Q3)

An object is placed 15 cm in front of a converging lens of focal length 10 cm.

Image distance:

1f=1u+1v\frac{1}{f} = \frac{1}{u} + \frac{1}{v}f1​=u1​+v1​

1v=1f−1u=110−115=330−230=130\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{1}{10} - \frac{1}{15} = \frac{3}{30} - \frac{2}{30} = \frac{1}{30}v1​=f1​−u1​=101​−151​=303​−302​=301​

v=30cmv = 30 \text{cm}v=30cm

The image is 30 cm from the lens on the other side.

Magnification:

m=vu=3015=2m = \frac{v}{u} = \frac{30}{15} = 2m=uv​=1530​=2

Nature: real, inverted, and magnified (twice the object height). The image is on the opposite side of the lens from the object.

Example/Converging lens with object inside F (magnifying glass) (2015 Paper 02, Q6)

An object AB is placed 20 cm from a converging lens of focal length 10 cm.

1v=110−120=220−120=120\frac{1}{v} = \frac{1}{10} - \frac{1}{20} = \frac{2}{20} - \frac{1}{20} = \frac{1}{20}v1​=101​−201​=202​−201​=201​

v=20cm (real image, same distance as object)v = 20 \text{cm (real image, same distance as object)}v=20cm (real image, same distance as object)

m=2020=1m = \frac{20}{20} = 1m=2020​=1

The image is real, inverted, and the same size as the object (object at 2F2F2F).

Applications of Lenses

ApplicationLens typeUse
Magnifying glassConvergingObject inside FFF, produces upright, magnified virtual image
CameraConvergingObject beyond 2F2F2F, produces real, inverted, diminished image on sensor
ProjectorConvergingObject between FFF and 2F2F2F, produces real, inverted, magnified image on screen
Spectacles (long-sight)ConvergingConverges light before it enters the eye to focus on the retina
Spectacles (short-sight)DivergingDiverges light before the eye so the eye can focus it
MicroscopeTwo converging lensesObjective lens forms a magnified real image; eyepiece magnifies it further
Exam Tip

Use 1/f=1/u+1/v1/f = 1/u + 1/v1/f=1/u+1/v consistently. A common error is adding 1/u+1/v1/u + 1/v1/u+1/v when you should subtract: rearrange carefully.

When describing the nature of an image, always state four things: real or virtual, upright or inverted, magnified or diminished (or same size), and on which side of the lens it lies.

Previous in syllabus order
Refraction and Total Internal Reflection
Next in syllabus order
Electrostatics